The aspect ratio of an image is the proportional relationship of the width to the height. You will recognize it as two numbers separated by a colon in an x:y format.x is the domain and y is the result area or range. mc007-1.jpg ⇒ q (x) = 5 (x-1) ---> is assumed from browsing. Subtracts from the two functions p (x) and q (x): Learn more. statement about f (x).mc008-1.jpg; mc008-2.jpg; mc008-3.jpg; mc008-4.jpg. Jpg is a picture extension of a file name. Why you are using such in your math?? Get the question straight, ask how to do the question rather than what the answers areAnswer: The domain of the function (f*g)(x) = {x|x≠4/5} Option C. Step-by-step explanation: First, you need to combine the functions f(x) and g(x) into the new function equation (f*g)(x). This looks complicated, but the first pair of parenthesis make it confusing.e. mc018-2.jpg. Question 16. mc016-1.jpg. A conservative force has the potential energy function U(x), shown by the graph above. A particle moving in one dimension under the influence of this force has kinetic energy 1.0 joule when it is at position x1 Which of the following is a correct statement...
If p(x) = x2 - 1 and mc007-1.jpg, which expression is... - Brainly.ph
Search for jobs related to Which expression is equivalent to mc011 1.jpg mc011 2.jpg mc011 3.jpg 2 4 or hire on the world's largest freelancing marketplace with 19m+ jobs. It's free to sign up and bid on jobs.MC-3615 - Lava and water are completely transparent at certain height levels. MC-46650 - When flying through blocks in spectator mode in F5 , the camera zooms in and out a lot. MC-53518 - Endermen don't attack endermites spawned using spawn eggs or /summon .which expression is equivalent to mc018-1.jpg? Solve and graph the solution set on a number line: (2x/5) + 1 < -3; x ∈ R.Answers is the place to go to get the answers you need and to ask the questions you want. One of the different types of graphs is the circle graph.
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If mc018-1.jpg and g(x) = 5x - 4, what is the domain of mc018-2.jpg? 1. See answer.Use approved domains when posting. Meet the minimum account age and karma thresholds. Don't flood new. Also, there aren't male futas exactly because futas are the peak of human evolution, and having no need of males only prove it further, because futas aren't neither male or female, they're both.(IMG:https://a.radikal.ru/a24/1905/bc/8bebae894c9f.jpg).Assume mc018-2.jpg. what expressions are equivilent to (4mn / m^-2 n^6)^-2 when M = 0 and N = 0. Vance used the associative property to write mc002-1.jpg as the equivalent expression mc002-2.jpg.what is yours?
I would like assist with this project thing, I'm a senior and horrible at math, this shouldn't be onerous for somebody who is just right at math. It's only Algebra 1. I need to move this magnificence to graduate and at this time I'm barely passing with a C. At most colleges a D is regarded as passing however at mine it's failing. ): Please please please lend a hand. I've long gone to math tutors and the whole lot I simply don't comprehend it!
1.
The equations of four strains are given. Identify which lines are parallel.
Line 1: y = mc002-1.jpgx + 5
Line 2: x + mc002-2.jpgy = 8
Line 3: y = mc002-3.jpgx – 9
Line 4: y + 9 = mc002-4.jpg(x + 9)
A) Lines 1 and 2 are parallel.
B) All 4 lines are parallel.
C) Lines 1 and 4 are parallel.
D) Lines 2 and Three are parallel.
2.
The equations of four traces are given. Identify which traces are parallel.
Line 1: y = mc006-1.jpgx – 2
Line 2: y + 5 = mc006-2.jpg(x + 7)
Line 3: y = mc006-3.jpgx + 9
Line 4: x – mc006-4.jpgy = –2
A) All four strains are parallel.
B) Lines 1 and 4 are parallel.
C) Lines 2 and 4 are parallel.
D) Lines 2 and Three are parallel.
3.
Identify the traces which can be perpendicular:
mc008-1.jpg; mc008-2.jpg; mc008-3.jpg; mc008-4.jpg
A) None of the strains are perpendicular.
B) mc008-14.jpg and mc008-15.jpg are perpendicular.
C) mc008-16.jpg and mc008-17.jpg are perpendicular.
D) mc008-18.jpg and mc008-19.jpg are perpendicular; mc008-20.jpg and mc008-21.jpg are perpendicular.
4.
Identify the lines which are perpendicular:
mc011-1.jpg; mc011-2.jpg; mc011-3.jpg; mc011-4.jpg
A) None of the traces are perpendicular.
B) mc011-14.jpg and mc011-15.jpg are perpendicular.
C) mc011-16.jpg and mc011-17.jpg are perpendicular.
D) mc011-18.jpg and mc011-19.jpg are perpendicular; mc011-20.jpg and mc011-21.jpg are perpendicular.
5.
Write an equation in slope-intercept form for the line parallel to y = mc013-1.jpgx – Nine that passes via the level (–9, –9).
A) y = mc013-9.jpgx – 9
B) y = mc013-10.jpgx – mc013-11.jpg
C) y = mc013-12.jpgx – mc013-13.jpg
D) y = mc013-14.jpgx + mc013-15.jpg
6.
Write an equation in slope-intercept shape for the line perpendicular to y = mc014-1.jpgx – 9 that passes via the point (–5, –9).
A) y = mc014-9.jpgx – mc014-10.jpg
B) y = mc014-11.jpgx – mc014-12.jpg
C) y = mc014-13.jpgx – 9
D) y = mc014-14.jpgx + mc014-15.jpg
7.
Write an equation in slope-intercept form for the line perpendicular to y = mc019-1.jpgx + Nine that passes via the level (4, 9).
A) y = mc019-9.jpgx + 9
B) y = mc019-10.jpgx – mc019-11.jpg
C) y = mc019-12.jpgx + mc019-13.jpg
D) y = mc019-14.jpgx + mc019-15.jpg
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