Solve for b a^2+b^2=c^2.The solution set of the equation is. , 2a 2a. where ∆ = discriminant = b2 − 4ac. 32. The roots are real and distinct if ∆ > 0.(a+b)(a2-ab+b2)=a3+b3.(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc. (a + b)n = an + nan - 1b + n(n - 1)2an - 2b2 + + n!k!(n - k)!an - kbk + + bn.We need more information to answer the question though. For example, if a, b, and c are the lengths of 3 perpendicular vectors in 3 dimensional space, and if you add these three vectors together to get a new vector d, then d^2 = a^2 + b^2 + c^2.
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Разность квадратов a 2 - b 2 = (a + b)(a - b).(a + b)3 = a3 + 3a2b + 3ab2 + b3. (a + b)2 = a2 + 2ab + b2 (a - b)2 = a2 - 2ab + b2 a2 - b2 = (a - b) (a+b) (a + b)3 = a3 + 3a2b + 3ab2 + b3 (a - b)3 = a3 - 3a2b + 3ab2 - b3 a3 + b3 = (a + b) (a2 - ab +.Докажите тождество : (a^2 — b^2 — c^2) — (b^2 — c^2 + a^2) + (b^2 — a^2) = -a^2 — b^2.The above formula gives a partial answer to your question, in that it tells us the number of solutions of the equation $a^2+b^2=c^2+d^2=N$, where order does not matter,and we allow only non-negative integers in the representation.
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(4a^2/(2a - b)):(12a^3/(4a^2 - b^2)):(2a^2/(6a^2 - 3ab)).Find the value of a2 + b2 + c2. SolutionВыразить b² из формулы b²=c²-a².(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc.a-b2=a2-2ab+b2. запишем
Теорема Пифагора для прямоугольного треугольника. Значит у треугольника есть катет, катет, гипотенуза.
Если ищем гипотенузу: гипотенуза (в квадрате) =катет (в квадрате) +катет (в квадрате)
Если ищем катет: катет (в квадрате) =гипотенуза (в квадрате) -катет (в квадрате)
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